jdoerfert added a comment.

In D85878#2217408 <https://reviews.llvm.org/D85878#2217408>, @JonChesterfield 
wrote:

> If I recall correctly, &foo with variants of foo returns a pointer to the 
> base.

Correct.

> If we have no base, and disable_implicit_base, what does &foo yield? It 
> should probably be a compilation error with some descriptive message

undefined symbol foo, or whatever message we emit if you use a variable that 
doesn't exist. A function definition `bar` inside of `begin/end declare 
variant` is *not* a function `bar`. It is a variant of a base function that 
exists or that we assume to exist (=implicitly declare).


Repository:
  rG LLVM Github Monorepo

CHANGES SINCE LAST ACTION
  https://reviews.llvm.org/D85878/new/

https://reviews.llvm.org/D85878

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