On Mon, 5 Jan 2009, Joseph L. Casale wrote: >> The regex you want is "^[[:space:]]*word" > > Wow, thanks everyone for the help! How does one modify this to also > knock out lines that *must* have whitespace followed by a number > [0-9]? I can do it using "^[[:space:]]*[0-9]" but it also takes out > lines w/o whitespace that begin with numbers?
Probably something like "^[[:space:]]\+[0-9]" -- though that assumes you're using gawk (since the \+ modifier is GNU-specific). For non-GNU awks, "^[[:space:]][[:space:]]*[0-9]" > I have to buy a book on RegEx's and Sed :) Good idea! -- Paul Heinlein <> heinl...@madboa.com <> http://www.madboa.com/ _______________________________________________ CentOS mailing list CentOS@centos.org http://lists.centos.org/mailman/listinfo/centos
