On Thu, 13 Dec 2007, Nuno Lucas wrote: > Explaining a bit more what I had mean, you are doing an 8-bit shift on > a char. Some compilers will first convert the value to int and then do > the shift, while others will apply the shift to the 8-bit value > (meaning the result will always be 0). > > I don't know what the C standard says about this, but as I have been > bitten by this before I always use proper casts to avoid any problems > on the day I decide to copy/paste some old code. > > It's possible you will have no problems with this code, though (maybe > recent compilers all do the right thing now). > > > Regards, > ~Nuno Lucas >
Well I'm pretty sure that it doesn't REALLY work this way, but I didn't write that part of code :) Thanks for the warning though ;) Thanks everyone! Ivan ------------------------------------------------------------------------- SF.Net email is sponsored by: Check out the new SourceForge.net Marketplace. It's the best place to buy or sell services for just about anything Open Source. http://ad.doubleclick.net/clk;164216239;13503038;w?http://sf.net/marketplace _______________________________________________ Cegcc-devel mailing list Cegcc-devel@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/cegcc-devel
