Look at the chain packing in your solution. If the solution is grossly
correct you will notice nice solvent channels and no glaring chain-size
holes and no gross overlaps. The initial maps should look sensible, if
noisy.

If the protein is composed of likely dimers, try a search with dimer units
to simplify the search.

Good luck.

__________________
Roger Rowlett

On Wed, Nov 13, 2019, 10:33 AM Robert S Phillips <p...@uga.edu> wrote:

> I have been working on a protein structure which has been hard to solve by
> molecular replacement.
>
> Unit cell: (60.6, 172.34, 196.42, 90, 90, 90)
> Space group: P 21 21 21
>
> The problem is that the homologues have only ~20% identity, and there are
> multiple chains in the asymmetric unit.  The question is how many.  It
> could be 4, 5, or 6 chains.
>
> N      solvent                           P
>  4      0.602           3.09            0.225
>  5      0.502           2.47            0.388
>  6      0.403           2.06            0.229
>
> I have run PHASER with 4, 5 and 6 chains.  I allowed it to search all
> possible space groups, and P212121 was the best solution.  These are the
> results.
>
> N          LLG           TFZ
> 4          104.9        7.5
> 5          137.5        7.7
> 6          166.2        8.3
>
>  Am I correct to conclude that there are 6 chains in the asymmetric unit?
>
> Rob
>
> Robert S. Phillips
> Professor of Chemistry and of Biochemistry and Molecular Biology
> University of Georgia
> Athens, GA 30602
> Phone: (706) 542-1996
> Fax: (706) 542-9454
> E-mail: rsphill...@chem.uga.edu
> Web:  http://tryptophan.net
> <https://pod51004.outlook.com/owa/redir.aspx?C=ccbf42ffea5f48b1bf8e9bb950454bab&URL=http%3a%2f%2ftryptophan.net>
>
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