PAK=0 is GOOD - i.e. there are no clashes between symmetry equivalent molecules. So I think you have solved your structure. Eleanor
On 15 September 2017 at 07:20, rohit kumar <rohit...@gmail.com> wrote: > Dear all, > > During MR using PHASER with a 1.8 A data, I found that the PAK=0 but all > the other values are looking fine. > > When I run REFMAC5 the R/Rfree values are 25/30 (without water) and 21/26 > (after adding water). > > Just want to know whether my solution is correct or not. if not please let > me know what strategies I can use to get correct solution. > As I have tried all the combination in PHASER. > > Here I am attaching the result of PHASER . > > > > [image: Inline image 3] > > > Thank you in advance > > -- > WITH REGARDS > Dr. Rohit Kumar Singh > >