On Tue, Jul 24, 2012 at 10:33 AM, Ethan Merritt <merr...@u.washington.edu> wrote: > As to the home source - no. > Neither Cu nor Zn has appreciable anomalous signal when excited with a > Cu K-alpha home source. > http://www.bmsc.washington.edu/scatter > > An element's emission edge (Cu K-alpha in this case) is about 1 keV below > the corresponding absorption edge. This makes sense, because after > absorbing a photon it can only emit at an equal or lower energy, not a > higher energy. So you can't reach the Cu absorption edge, where the > anomalous signal is, by exciting with Cu K-alpha.
Oops, sorry, I was of course comparing the wrong numbers. -Nat
