I would think that bond should be the same distance (within hundredths of an Ã…ngstrom) as the other 5 carbon-carbon bonds in the benzene ring. That whole molecule is aromatic, by the way.

I can't answer the "how come" question except to say that is most likely wrong, due to making wrong assumptions about the hybridization state of the relevant atomic orbitals, I guess.

phenix.elbow will probably do a better job. It even has an option for using a quantum-mechanics-based geometry optimization.

Your intuition is right: those bonds should be extremely close to the same distances as those found in benzene and imidazole.


On Sep 24, 2009, at 1:06 AM, Zheng Zhou wrote:

Thanks Bill for clarifying the notion of aromatic bonds

I think the C-C bond shared by the benzene and imidazole ring should
be close to a double bond distance

http://en.wikipedia.org/wiki/Benzimidazole

How come calculation from monomer sketcher and the BZI entry in the
library has a distance close to a single bond?

Joe

On Thu, Sep 24, 2009 at 12:36 PM, William G. Scott
<wgsc...@chemistry.ucsc.edu> wrote:

On Sep 23, 2009, at 5:03 PM, Zheng Zhou wrote:

Is there a clear definition of delocalized bond or armatic bond?


Hi Zheng:

Aromatic bonds only occur in planar cyclic molecules that have 4n +2 pi electrons. Aromatic interactions give energetic stabilization beyond that observed for delocalized conjugated systems, for example, the aromatic stabilization of benzene is the energy difference between real benzene and a
hypothetical set of resonance structures representing delocalized
1,3,5-cyclohexatriene. Similarly, anti-aromatic interactions occur in planar cyclic molecules having 4n pi electrons; they are destabilized relative to their hypothetical cycloalkene counterparts. (If you allow for perpendicular aromatic interactions, Hoffmann and Goldstein in 1971 demonstrated that 4n
pi electrons in that case are also stabilizing, due to the different
topology of the pi electron interactions, something that may be of relevance
to aromatic side chain clusters.)

HTH,

Bill

Reply via email to