Hi there This is regarding vol. 1 lab 19 task 16.11
task 16.11 option #3 access-list 3 deny 129.150.17.0 96..64.255 access-list 3 deny 97.150.81.0 0.0.0.255 the subnet of 129.150.17.0 --------> this subnet will give up 3 subnets 129.150.17.0 193.150.17.0 161.150.17.0 now what about the subnet 225.0.0.0. how he get it? I know of is the that 129.150.17.0 96.0.64.255 128 192 224 240 248 252 254 255 -------- > block # 128 64 32 16 8 4 2 1 Therefor, the correct answer will this 224.0.0.1 as broadcast address 129.150.17.0 193.150.17.0 161.150.17.0 224.0.0.1 correct me if i AM wrong khaled thanks, _______________________________________________ For more information regarding industry leading CCIE Lab training, please visit www.ipexpert.com Are you a CCNP or CCIE and looking for a job? Check out www.PlatinumPlacement.com http://onlinestudylist.com/mailman/listinfo/ccie_rs
