Thank you very much. I didn't notice that the 5.x manual page is having a 
use case description since I am using 4.2.x and keep reading the 4.2.x 
documentation. (and google always show me doc pages of old CAS website)

I think this matches Gangadhar's use case. 
However for my case, it is not App-A consuming App-B but the client 
contacting App-B directly by client side ajax request to get data. Is CAS 
covering this kind of use case?

Thanks a lot.
C.C.

On Thursday, January 26, 2017 at 3:42:42 PM UTC+8, Misagh Moayyed wrote:
>
> And did you get a chance to read this, which describes exactly what you’re 
> explaining here?
>
> https://apereo.github.io/cas/5.0.x/installation/Configuring-Proxy-Authentication.html
>  
>
> -- 
> Misagh
>
> From: Gangadhar Vulpay <[email protected]> <javascript:>
> Reply: [email protected] <javascript:> <[email protected]> <javascript:>
> Date: January 26, 2017 at 5:15:03 AM
> To: CAS Community <[email protected]> <javascript:>
> Subject:  Re: [cas-user] Re: CAS Proxy vs CAS Rest protocol 
>
> Right now we are planning to protect Application B by CAS. But as part of 
> initial changes we are trying not to change application C (I mean NO Not 
> protected by CAS).  
>
>
> On Wednesday, January 25, 2017 at 6:02:44 PM UTC-5, Misagh Moayyed wrote: 
>>
>> Are applications B and C protected by CAS too?
>>
>> On Thursday, January 26, 2017 at 12:45:17 AM UTC+3:30, Gangadhar Vulpay 
>> wrote: 
>>>
>>> Hi Misagh, 
>>>
>>> I vary sorry for not clear about by question.
>>>
>>> I was trying to do a POC using CAS SSO provider and below is my use case
>>>
>>> 1. Application A (Web Application) - Assume we make this Cassify 
>>> 2. Application B (Webservice) 
>>> 3. Application C (Webservice) 
>>>
>>> "App-A" get the data from "App-B"(Webservice)  but this internally calls 
>>> App-C(Webservice)
>>>
>>> I was trying to understand what is the best way to do above use case. 
>>>
>>> I was thinking how to use CAS REST Protocol in this case but not clear 
>>> is this the right way to do this.
>>>
>>>
>>> Thanks,
>>> Ganga 
>>>
>>>>
>>>>

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