This WILL sound complicated.
Policy hasMany Notification / Notification belongsTo Policy Now the Notification can be A. internal (relating to specific content in the site, so the data is gathered directly , created by logged in user, what page Policy it pertains, other policy info, notification reason..) B. external (then the user fills out a form) and this is represented by Notification.local table field bool So now paginate Notifications easy enough until the JOINS condition Notification.user_id => $me, Policy.status => 1. Since external Notifications have no Policy.status those are not being pulled obviously. This is where the problem is. I have to keep the Policy.status for archive / record keeping legal mumbo jumbo so I simply can not delete a Notification, has to be marked read, fixed, outstanding, overdue. And all Nofifications must be in 1 page (pagination). I tried making an ExternalNotification model / controller but then I run into the issues of paginating 2 separate models as 1. If there is a way to find by( Notification.user_id => $me, Policy.status => 1) or (Notification.user_id => $me, Policy.status => does not exist?) Some other method suggestion, point me in a general direction. Thanks guys, K -- Our newest site for the community: CakePHP Video Tutorials http://tv.cakephp.org Check out the new CakePHP Questions site http://ask.cakephp.org and help others with their CakePHP related questions. To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php
