var $paginate = array(
                        'limit' => 20,
                        'order' => array(
                                'Person.fullname' => 'asc'
                        )
                        'joins' => array(
                                array(
                                        'table' => 'people_language',
                                        'alias' => 'PeopleLanguage',
                                        'type'  => 'left',
                                        'conditions' =>"People.oid =
PeopleLanguage.people_oid"
                                )
                        )
                );

As in your variant you tell cake that "people_language.people_oid" is
a string value, not a table field reference. And always use aliases
for tables.

On Jan 20, 5:15 am, Rangi <[email protected]> wrote:
> Hello,
>
> CakePHP is building a query like this:
> (this is just a snippet, but enough to show the problem)
>
> SELECT COUNT(*) AS "count" FROM "people" AS "People" left JOIN
> people_language  ON ("People"."oid" = 'people_language.people_oid');
>
> Postgres returns an error when CakePHP tries to run this, because
> 'people_language.people_oid' shouldn't be in single quotes. It should
> be either:
>
> people_language.people_oid
> OR
> "people_language"."people_oid"
>
> The code I'm running for this to happen is:
>
>         class PeopleController extends AppController {
>
>             var $paginate = array(
>
>                         'limit' => 20,
>                         'order' => array(
>                                 'Person.fullname' => 'asc'
>                         )
>                         'joins' => array(
>                                 array(
>                                         'table' => 'people_language',
>                                         'type'  => 'left',
>                                         'conditions' => array("People.oid" =>
> "people_language.people_oid")
>                                 )
>                         )
>                 );
>
>             function index() {
>                    $data = $this->paginate();
>             }
>         }
>
> Does anyone know how I could correct this?
>
> Any help much appreciated,
> Rangi
Check out the new CakePHP Questions site http://cakeqs.org and help others with 
their CakePHP related questions.

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