$this->paginate['fields'][] = "Model.first_name as example"; OR:
array_push($this->paginate['fields'], 'Model.first_name as example'); On Wed, Oct 7, 2009 at 7:00 PM, Kyle Decot <kdec...@gmail.com> wrote: > > I want to append a dynamically created field to my paginated results > but when I do > > $this->paginate['fields'] = "Model.first_name as example"; > > It only pulls in that field when what I really want is all the fields > it would normally get, plus this one. Is there a way to do this? Thanks > > > --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "CakePHP" group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~----------~----~----~----~------~----~------~--~---
