How about $modelName = key($this->params['paging']);
That should do the trick. hth grigri On Jul 20, 11:47 am, jordicakephp <[email protected]> wrote: > Hi again, my dear baker friends. > > Until now, when I've written this in a controller: > > $paginatedQuery = $this->paginate($this->modelClass); > > I've coded this in a view to access the information that it returns > (inside a foreach loop, of course): > > $row['ModelName']['user_login'] > > That is, hard-coding the name of the model in the view. My doubt is: > How can I access, from a view, the name of its associated model? I > haven't been able to find this answer! > > Again, thanks a lot in advance for your time (I promise not to write > more messages today ;-) --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "CakePHP" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~----------~----~----~----~------~----~------~--~---
