Even if i use array_push($this->data['Genre']['id'], 51); without the conditional statement it still doesn't add 51 to the Genre id array. $this->data['Genre'][] = 51; doesn't work either. I've tried a few variations and can't get it to work. First I need to figure out how to add values to the $this->data array and then I can focus on the conditional statement.
On Jan 22, 5:42 pm, brian <[email protected]> wrote: > if (isset($this->data['Genre']['id']) && > is_array($this->data['Genre']['id']) && !in_array('51', > $this->data['Genre']['id'])) > { > $this->data['Genre'][] = 51; > // or, array_push($this->data['Genre'], 51); > > } > On Thu, Jan 22, 2009 at 8:28 PM, kai <[email protected]> wrote: > > > In $this->data: > > [Genre] => Array > > ( > > [id] => Array > > ( > > [0] => 2 > > [1] => 55 > > ) > > > ) > > In sql: > > WHERE `Genre_id` IN ('2', '55') > > > Yeah, I want to add to their selection, not override it. > > > On Jan 22, 5:21 pm, brian <[email protected]> wrote: > >> If a user "chooses a genre" what does the data look like? Before your > >> code does anything. Is it well formed? > > >> If you want to set ['Genre']['id'] to some value, what does the data > >> look like before that? It seems like you're trying to override the > >> user's selection, rather than add to it. Do you want to add ID=51 *in > >> addition* to whatever genre ID the user passes? > > >> On Thu, Jan 22, 2009 at 8:09 PM, kai <[email protected]> wrote: > > >> > When a user submits a form I'm hoping to apply some logic to their > >> > choice. The form takes user input and translates their selection into > >> > conditions to use in a query. One part of the selection is the choice > >> > to choose a genre. I'm hoping to say something like, if user chooses > >> > one genre or more then also add 'this genre' to their query. I tried > >> > something like: > > >> > if (!empty($this->data['Genre']['id']) and count($this->data['Genre'] > >> > ['id']) > 0) { > >> > $this->data['Genre']['id'] = 51; > >> > } > > >> > but have found that $this->data['Genre']['id'] = 51; does nothing. How > >> > can i force genre 51 to become part of the query if the user chooses > >> > at least one genre? --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "CakePHP" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~----------~----~----~----~------~----~------~--~---
