$modelname = 'Hotel'
${$controllername} = $this->Hotelinfo->$modelname->find('list');Seams to work. Sometimes life is easier than expected ;-) Anja -----Ursprüngliche Nachricht----- Von: cake-php@googlegroups.com [mailto:[EMAIL PROTECTED] Im Auftrag von Liebermann, Anja Carolin Gesendet: Mittwoch, 8. Oktober 2008 11:00 An: cake-php@googlegroups.com Betreff: Dynamic model names in loop - possible? Hello everybody, I have a loop and want to set the linked object name dynamically: Now : ${$controllername} = $this->Hotelinfo->Hotel->find('list'); As you can see I have already the variable dynamically named. Now i want to replace 'Hotel' by a varibale. Something like: ${$controllername} = $this->Hotelinfo->$modelname->find('list'); Is this possible? If yes waht would be the correct syntax? Thank you for any hints! Anja --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "CakePHP" group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~----------~----~----~----~------~----~------~--~---
