Hi,
I've been using google for too long now and I still haven't found what
I am looking for. I'm just trying to submit a form using ajax (Cake
1.2) and I'm going through hell. It is supposed to be simple with
cakephp so I must be really bad... Without ajax it works.
Here's my form :
<?php echo $ajax->form('index', 'post', array('update' => 'content',
'id' => 'testform')); ?>
<?php echo $form->input('critere_tri', array('options' =>
array("Participant.magasin_id" => "Magasin"))); ?>
<?php echo $ajax->submit("Go! Go! Go!", array("with" => "testform")); ?
>
<?php pr($data); // To verify if the request is successful ?>
The controller :
class CreationsController extends AppController
{
var $name = "Creations";
var $components = array("Auth");
var $uses = array("Participant", "Creation");
var $helpers = array('Form', 'Ajax');
function index()
{
if(!empty($this->data)
$this->set($this->data); // To verify if the request is
successful
$this->set("participantsMagasinCreations", $this->Participant-
>findAll());
}
}
I want to get the value from the list and use it in the findAll()
order condition. For the moment I just display it. But it doesn't
work.
There's the following javascript error : "testform is not defined".
And I checked in the source of the document, the form has
"id='testform' ...
Thanks in advance for helping me.
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