http://codejanitor.com/wp/2006/03/23/ajax-timeouts-with-prototype/
On Apr 10, 1:02 am, "skyblueink" <[EMAIL PROTECTED]> wrote: > Sorry, this is not CakePHP stuff, but javascipt stuff. > > When we fire a javascript function through "onLoad" event, it works > through two steps like the following: > (1) First, the page is loaded. > (2) Javascript function is fired. > > This is the definition of onLoad event, and we all know that the STOP > button on any browsers functions only while a page is being loaded, > that is during the step (1). It means that once page loaing is done in > step(1), and javascript function is fired in step (2), the STOP button > on the browsers gets useless. What I really want to know is "Are there > any ways to stop javascript execution in step (2)?" > > I have a page containing 10 <div> and 10 onLoad javascript functions > which populates the <div>s through AJAX. In this case, page loading in > step (1) is very fast (less than 1 second), but since populating > <div>s takes 30-40 second, I'd like to provide the users with STOP > button which works in step (2). --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Cake PHP" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~----------~----~----~----~------~----~------~--~---
