Em segunda-feira, 3 de novembro de 2014 06:51:20 UTC-2, Jitendra Rathod 
escreveu:
>
> In cakephp 2.2.x, we can have automatic join work for cross databases with 
> a simple patch:
>
> "lib/Model/Datasource/DboSource.php function read()
> if ($model->useDbConfig === $linkModel->useDbConfig) {
> ...
>
> to 
> if ($model->useDbConfig === $linkModel->useDbConfig || $type=='belongsTo') 
> {
> ...
>
> But in recent 2.5.x, the read function seems have some changes, 
> I was wondering how to make the cross database auto join for belongsTo ?
>

------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------

People a have similar problem. In my database bustracker_db i have generic 
stuff, like(Model cars, Type of contacts)

public $default = array(
        'datasource' => 'Database/Mysql',
        'persistent' => false,
        'host' => 'xxxx',
        'login' => 'xxxx',
        'password' => 'xxxx',
        'database' => 'bustracker_sca_db',
        'prefix' => '',
        'encoding' => 'utf8'
    );
        
 public $bustracker = array(
        'datasource' => 'Database/Mysql',
        'persistent' => false,
        'host' => 'xxxx',
        'login' => 'xxxx',
        'password' => 'xxxx',
        'database' => 'bustracker_db',
        'prefix' => '',
        'encoding' => 'utf8'
    );

In my *FuncionarioController* a put: public $uses = array('Funcionario', 
'FuncionariosContato', 'ContatosTipo'); 

*Funcionario* and *FuncionariosContato* are in the same 
database(bustracker_sca_db') and ContatosTipo in bustracker_db. 

In *Funcionario* i put:

 public $hasMany = array(
        'FuncionariosContato' => array(
            'className' => 'FuncionariosContato',
            'foreignKey' => 'funcionarios_id',
            'dependent' => true
        )
    );
 
*FuncionariosContato* i put:

 public $hasOne = array(
            'ContatosTipos' => array(
            'className' => 'ContatosTipos',
            'foreignKey' => 'contatos_tipos_id',
            'conditions' => '',
            'fields' => '',
            'order' => ''
        )
);

A get this error:  Table *contatos_tipos* for model *ContatosTipos* was not 
found in datasource 

*default.*CakePhp try to find *contatos_tipos in the *datasource *default, 
but* i change $useDbConfig for $useDbConfig = 'bustracker'.

I try many different ways to solve this.

Thanks.

-- 
Like Us on FaceBook https://www.facebook.com/CakePHP
Find us on Twitter http://twitter.com/CakePHP

--- 
You received this message because you are subscribed to the Google Groups 
"CakePHP" group.
To unsubscribe from this group and stop receiving emails from it, send an email 
to cake-php+unsubscr...@googlegroups.com.
To post to this group, send email to cake-php@googlegroups.com.
Visit this group at http://groups.google.com/group/cake-php.
For more options, visit https://groups.google.com/d/optout.

Reply via email to