Hmm, yes. After do something like this:
$url = Router::parse($redirect);
$params = $url['params'];
unset($url['params'])
$redirect = Router::url(array_merge($url, $params))
On Thursday, March 19, 2015 at 6:32:07 PM UTC+1, Pgbi wrote:
>
> The reason i need to parse and generate again an url is in the example I
> gave in my first message:
> In my App, when a user logs in, he is redirected to
> $this->Auth->redirectUrl() which is of the form
> /locale/controller/action/param . Before redirecting him, I want to replace
> "locale" with $user->locale. So I parse the url, replace the locale
> parameter, and generate the url again.
>
> Does it make sense :) ?
>
>
> Le jeudi 19 mars 2015 02:09:10 UTC-7, José Lorenzo a écrit :
>>
>> Router::url() and Router::parse() are not symmetrical. I don't see the
>> reason why you want to parse the url and the pass it again to the Router.
>> Could you explain?
>>
>>
>> On Thursday, March 19, 2015 at 1:00:16 AM UTC+1, Pgbi wrote:
>>>
>>> Tell me if i'm wrong but i thought that Router::parse was the inverse of
>>> Router::url.
>>> In other words, I thought that $url ==
>>> Router::url(Router::parse($url))would
>>> always be true.
>>>
>>> Just found out this was not the case.
>>>
>>> If $url = "/users/view/123" then Router::url(Router::parse($url)) =
>>> "/users/view?pass%5B0%5D=123"
>>>
>>> This leads to the following bug in my App:
>>>
>>> // In UsersController
>>> function login()
>>> {
>>> if ($this->request->is('post')) {
>>> $user = $this->Auth->identify();
>>> if ($user) {
>>> $this->Auth->setUser($user);
>>> $url = $this->Auth->redirectUrl(); // let's say redirect url
>>> is "/en/users/view/123"
>>> $url = Router::parse($url); // now url is ['controller' =>
>>> 'users', 'action' => 'view', 'locale' => 'en', 'pass' => ['123']]
>>> $url['locale'] = $user['locale']; // my user is french
>>> $url = Router::url($url); // now url is
>>> "/fr/users/view?pass%5B0%5D=123"
>>> instead of "/fr/users/view/123"
>>> return $this->redirect($url);
>>> }
>>> }
>>> }
>>>
>>
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