I put this in AppController beforeFilter:
if ($this->request->is('ajax')) {
Configure::write('debug', 0);
$this->autoRender = false;
$this->layout = 'ajax';
$this->disableCache();
}
On 13 Mar 2014, at 11:29, Wladimir Chopite <[email protected]> wrote:
> Use at the beginning of your controller function:
>
> $this->autoRender=false;
>
>
> Wladimir Chópite
> +584249700264
> ve.linkedin.com/in/wchopite
> "Mejor pirata de la armada". Hack the planet!
>
> El 13/03/2014 06:57, "Sam" <[email protected]> escribió:
>
>
> On Thursday, March 13, 2014 7:21:26 PM UTC+8, wchopite wrote:
> Use the php function json_encode( ).
>
> http://php.net/manual/en/function.json-encode.php
>
> You can generate an associative array with the message you want, and use:
>
> return json_encode($your_array);
>
> Thanks. This worked. I can see the json message in the HTTP response. But I
> still have a problem. When I look at the HTTP response, it is full of other
> HTML code besides the json message. How can I remove the other HTML code and
> leave behind only a clean json message?
>
> Thank you.
>
> Wladimir Chópite
> +584249700264
> ve.linkedin.com/in/wchopite
> "Mejor pirata de la armada". Hack the planet!
>
> El 13/03/2014 06:45, "Sam" <[email protected]> escribió:
> I have a controller which takes in an id and checks whether this id exists
> inside the Model. If it does not exist, I would like the controller to return
> a validation error message "id not found" in json when it returns the HTTP
> response. This controller takes in a normal HTTP POST which is not in json.
>
> How can this be done in Cakephp 2.4.5?
>
> My controller code looks something like this;
>
> public function controller_function($id=null)
> {
> if ($this->request->is('post'))
> {
> $field=$this->request->data['Model']['field'];
> $Model_id = $this->Model->findFieldID($field);
> if (empty($Model_id) ) //record not found. Return validation error
> {
> //Send validation error back in JSON. How??
> }
> }
> }
>
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