IMO findBy magic methods expect a value to be passed, not an SQL expresión.
You are better of using findAll() with SQL expressions.
$results = $this->Customer->findAll(array('address'=>"LIKE
%{$searchTerm}%"));
if ($results !== false && isset($results[0]))
{
$results = $results[0];
}
-MI
---------------------------------------------------------------------------
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BAKE ON!
-----Mensaje original-----
De: [email protected] [mailto:[EMAIL PROTECTED] En nombre
de [EMAIL PROTECTED]
Enviado el: Lunes, 11 de Diciembre de 2006 09:40 p.m.
Para: Cake PHP
Asunto: like clause not working
$results = $this->Customer->findByAddress("LIKE %{$searchTerm}%");
keeps returning false.
However, if I use query() with an appropriate sql statement, I get
results just fine.
Is there something I'm missing?
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