Thanks for the reply. So in the above scenario (contain reference to 'SurveyRespose') I would need to load the 'SurveyResponse' Model as it is not related to the 'Booking' Model?
On Mar 12, 2:25 pm, euromark <[email protected]> wrote: > no > not if there is a relation between those models and you properly access it > via chain: > > $this->Booking->SurveyResponse->find(); > etc > > Am Montag, 12. März 2012 13:32:32 UTC+1 schrieb Kro: > > > > > > > > > > > I have removed 'var $uses' from a controller and replaced it with > > calls to 'loadModel()'. I'm just wondering if I need to load a model > > which isn't referenced directly in a function, but is referenced in a > > contain. > > e.g. > > > $contain = > > array('SurveyResponse'=>array('SurveyQuestion'),'BookingOrder'=>array('Room > > ','Rate','AddOnPurchase'=>array('AddOn'))); > > // > > Association between Booking and SurveyResponse in SurveyResponse Model > > $this->Booking->contain($contain); > > > Is it necessary to load the 'SurveyResponse' Model as it is mentioned > > in the above contain statement for the Booking Model? > > > Thanks -- Our newest site for the community: CakePHP Video Tutorials http://tv.cakephp.org Check out the new CakePHP Questions site http://ask.cakephp.org and help others with their CakePHP related questions. To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/cake-php
