Hello folks.
I have a question regarding parenthesis
in GNU-make macros. Like in:
msg = @echo "$(1)"
ptest_1:
$(call msg, foo (arg1, arg2, arg3))
ptest_2:
$(call msg, foo, arg1, arg2, arg3)
--------------------
A 'make ptest_1' shows:
foo (arg1, arg2, arg3)
and 'make ptest_2' shows:
foo
as I'd expect since the macro takes only one arg.
So does a "foo (arg1, arg2, arg3)" becomes one
argument due to the parenthesis or something?
I find this parsing a bit strange and inconsistent;
like a comma has no meaning in 'ptest_1'. I did not
find this "issue" in the manual.
GNU Make 4.3.90
Built for Windows32
--
--gv
