On 05/18/2015 11:28 AM, Lakshmana Rao Adabala, Shanmukha wrote: > Hi Team, > > I would like to know how to get the grep output in the same order. > > For example: > > I am using the following order : 04A2,17F5,04A4 > > [cid:image001.png@01D091AF.B34719B0]
Screenshots are hard to parse; it's better to paste actual screen text content. It looks like you are using Windows, due to the unusual quoting paradigms used on the command line: service@VPLEXCLU2:~> cat 852* | grep -E ""04A4"|"17F5"|"04A2"" On a Unix system, the quoting would be: cat 852* | grep -E "04A4|17F5|04A2" > > I am expecting output in the following order. > > 04A2 > 17F5 > 04A4 It sounds like you were hoping that grep would make three passes over your input stream (the concatenated 852* files) - first outputting all matches to the pattern 04A4, then all matches to the pattern 17F5, then all matches to the pattern 04A2. But that's not how grep works. It makes a single pass over your input, and for each line, it checks all alternations within the pattern at once. > > But I am getting the output in the below order > > 04A2 > 04A4 > 17F5 Which means that the first line that matched is one that matched your third alternative in the single pattern. > > Please let me if any additional switches to use. The only way to get output in a particular order is to do three separate passes of grep, on one non-alternating pattern each, rather than one pass with a three-alternation pattern. -- Eric Blake eblake redhat com +1-919-301-3266 Libvirt virtualization library http://libvirt.org
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