echo line1^ line2
Work also and could be simple Maybe echo line1^ \rline2 Will work with \r a not escaped carriage return Le 10 mai 2012 00:07, "Bruno Haible" <br...@clisp.org> a écrit : Bastien ROUCARIES wrote: > Something like this will work > http://stackoverflow.com/a/269819 Indeed! It allows to substitute newlines. $ export NL=' ' $ cmd.exe /c 'printf "%s\n" foo^%NL%%NL%bar' | od -t x1 0000000 66 6f 6f 0a 62 61 72 0a 0000010 But I don't succeed in getting a carriage-return character in the same way: $ eval `echo "export CR='_'" | tr '_' '\r'` $ cmd.exe /c 'printf "%s\n" foo^%CR%%CR%bar' | od -t x1 0000000 66 6f 6f 62 61 72 0a 0000007 Any idea how to get this one? And then there is also the problem with byte sequences that are not strings in the current locale encoding... Bruno
