Juhapekka Tolvanen wrote:
On Thu, 31 Dec 2009, +14:51:44 EET (UTC +0200),
Eric Blake pressed some keys:
According to Juhapekka Tolvanen on 12/30/2009 4:35 PM:
I wanted to do this: Give sizes of each files and directories located
in $PWD in human-readable-format AND sort output according to sizes of
those files and directories.
What's wrong with:
du -sh0 * | sort -hz | tr '\0' '\n'
besides needing coreutils 7.5 or newer?
What if size of one directory is rounded UP to 1M and size of other
directory is rounded DOWN to 1M? How sort-command can know know, which
one is bigger? I am sure, that sorting must be done according to size
in bytes, not according to size of human-readable units.
Okay. What is wrong with:
du -B 1 -s -0 * \
| sort -nz \
| awk -v RS='\0' '{print $2}' \
| xargs -d '\0' du -sh
?
Incidentally, instead of re-executing 'du' via xargs, I do this:
awk -v RS='\0' '{
if ( $1 > 0x3F000000 )
printf "%6.1fG\t", $1 / 0x40000000 ;
else if ( $1 > 0xF0000 )
printf "%6.1fM\t", $1 / 0x100000 ;
else if ( $1 > 0x300 )
printf "%6.1fK\t", $1 / 0x400 ;
else
printf "%6i\t", $1 ;
$1="" ;
print $0 ;
}'
...which has the advantage of being able to cope with a 'du -c' line
(not to mention better alignment and less disk I/O).
--
Matthew
Please do not quote my e-mail address unobfuscated in message bodies.
--
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are willing to lose money for years and years just to make sure that you
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