Hello,
Please look at the minimal working example below.
GNU bash, version 5.1.16(1)-release (x86_64-pc-linux-gnu)
Ubuntu 22.04.5 LTS
*01a.sh*
#!/bin/bash
set -e
echo "01a - 1 "
./02.sh
echo "01a - 2 "
*01b.sh*
#!/bin/bash
set -e
echo "01b - 1 "
./02.sh && echo "You will not see this"
echo "01b - 2 "
*02.sh*
#!/bin/bash
set -e
echo "02 - 1"
set +e
this_command_does_not_exist
RESULT=$?
set -e
echo "02 - 2 RESULT=$RESULT"
exit $RESULT
Outputs:
# ./01a.sh
01a - 1
02 - 1
./02.sh: line 6: this_command_does_not_exist: command not found
02 - 2 RESULT=127
# ./01b.sh 127 ↵
01b - 1
02 - 1
./02.sh: line 6: this_command_does_not_exist: command not found
02 - 2 RESULT=127
01b - 2
The 01a.sh script exists with code 127, the01b.sh script exists with code 0.
The only difference between them is that 01a.sh executes./02.shbut
01b.sh executes ./02.sh && echo "You will not see this"
According to the current bash documentation (output of "man bash"):
> An AND list has the form
>
> command1 && command2
>
> command2 is executed if, and only if, command1 returns an exit
status of zero (success).
>
> An OR list has the form
>
> command1 || command2
>
> command2 is executed if, and only if, command1 returns a
non-zero exit status. *The return status of AND and OR lists is the exit
status of the last*
> *command executed in the list.*
I think that there is a bug:
* ./02.shreturns error code 127
* ./02.sh && echo "You will not see this"should also return exit code
127 (because second command in the list is not executed)
* echo "01b - 2 "*should not be executed*, because "set -e" was
specified, but in reality it is executed
* The exit code of01b.shshould be 127 but in reality it is zero
Please let me know if this is indeed a bug.
Thank you,
--
*Nagy László Zsolt*
Szoftver tervező
Informatikai Fejlesztési Intézet, Eszterházy Károly Egyetem
--
*Nagy László Zsolt*
Software architect
Software Development Institute, Eszterházy Károly University
H-3300 Eger, Leányka utca 4.
