On Sat, Feb 8, 2025 at 10:31 AM Robert Elz <k...@munnari.oz.au> wrote:
> > > It isn't a valid form for a C constant. bash allows that kind of thing > in its arithmetic contexts, but this is not one. > > Jeez moving target, thanks to bring C in the loop I got it now :-) I like this orthogonality :-) $ printf '%d\n' 2#1 bash: printf: 2#1: invalid number 2 $ printf '%d\n' $((2#1)) 1 $ printf '%d\n' 0b1 1 $ printf '%d\n' $((0b1)) bash: 0b1: value too great for base (error token is "0b1") $ lol
