the printf %d gets to be no print_out at all u specify a %<code> but no arg means it wont try printf at all smth
printf %d '' we can talk about returns 0 and looks normal so to me On Tue, Nov 19, 2024, 8:46 PM Paul Eggert <egg...@cs.ucla.edu> wrote: > Configuration Information [Automatically generated, do not change]: > Machine: x86_64 > OS: linux-gnu > Compiler: gcc -std=gnu23 > Compilation CFLAGS: -g -O2 > uname output: Linux penguin.cs.ucla.edu 6.11.6-200.fc40.x86_64 #1 SMP > PREEMPT_DYNAMIC Fri Nov 1 16:09:34 UTC 2024 x86_64 GNU/Linux > Machine Type: x86_64-pc-linux-gnu > > Bash Version: 5.3 > Patch Level: 0 > Release Status: beta > > Description: > > printf doesn't diagnose attempts to print empty strings as numbers. This > doesn't conform to POSIX and disagrees with the traditional Unix printf > command. > > Repeat-By: > > printf %d '' > > This should behave like "printf %d ' '", and should output a diagnostic > and exit with status 1; instead it silently exits with status 0. > > Fix: > Attached.
