On 6/26/24 7:18 PM, Martin D Kealey wrote:
But unfortunately in this case, BASH_ARGC[0] is 1 rather than 0,, and the filename provided to "source" (now ${BASH_SOURCE[0]}) is prepended to BASH_ARGV.
Because that's the state of this call frame, and that's what the bash
debugger -- why these variables exist -- needs.
--
``The lyf so short, the craft so long to lerne.'' - Chaucer
``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, UTech, CWRU c...@case.edu http://tiswww.cwru.edu/~chet/
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