>
> What makes you think so? Variables are always visible in invoked
> functions, unless you shadow them using local/declare/typeset.
>
Thank you very much for this information, I didn't know invoked functions
inherited their parent functions variables.
I understand better now the use of declare -n "reference", to make a copy
of the referenced variable.
Best,
On Sat, Jul 1, 2023 at 10:38 PM Lawrence Velázquez <v...@larryv.me> wrote:
> On Sat, Jul 1, 2023, at 3:55 PM, Top Dawn wrote:
> > I believe there is a bug with associative arrays, when once referenced in
> > another function through the -n option, both the new reference name and
> the
> > old one are made available.
> >
> > ```bash
> >
> > #!/bin/bash
> > function my_function(){
> > declare -A my_array
> > my_array=(["one"]="one")
> > other_function "my_array"
> > }
> >
> > function other_function(){
> > declare -n other_array="${1-}"
> > echo "${other_array["one"]}"
> > echo "${my_array["one"]}"
> > }
> >
> > my_function
> >
> > ```
> >
> > will output :
> >
> > ```bash
> >
> > one
> > one
> >
> > ```
> >
> > I believe this to be a bug.
>
> What makes you think so? Variables are always visible in invoked
> functions, unless you shadow them using local/declare/typeset.
>
> % cat /tmp/foo.bash; echo
> function my_function(){
> declare -A my_array
> my_array=(["one"]="one")
> other_function
> }
>
> function other_function(){
> echo "${my_array["one"]}"
> }
>
> my_function
>
> % bash /tmp/foo.bash
> one
>
> --
> vq
>
