On 7/16/22 1:44 PM, Steffen Nurpmeso wrote:
Hello.I realized there is no unsigned right shift in bash arithmetic expression, and thought maybe there is interest.
Thanks. There aren't any unsigned operators in shell arithmetic now, what makes this one necessary? Chet -- ``The lyf so short, the craft so long to lerne.'' - Chaucer ``Ars longa, vita brevis'' - Hippocrates Chet Ramey, UTech, CWRU c...@case.edu http://tiswww.cwru.edu/~chet/