On 7/16/22 1:44 PM, Steffen Nurpmeso wrote:
Hello.

I realized there is no unsigned right shift in bash arithmetic
expression, and thought maybe there is interest.

Thanks. There aren't any unsigned operators in shell arithmetic now, what
makes this one necessary?

Chet

--
``The lyf so short, the craft so long to lerne.'' - Chaucer
                 ``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, UTech, CWRU    c...@case.edu    http://tiswww.cwru.edu/~chet/

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