Thanks Dennis and Grisha! I understand. I had thought that every line that is piped into bash is it's own shell alignment, but I understand it's more like sourcing, so these would be more or less equivalent, right?
r=23; echo $r; echo -e 'r=bc\necho $r' >r; source r r=23; echo $r; echo -e 'r=bc\necho $r' |bash Thanks again, Peter On 31/12/2559 11:07, Grisha Levit wrote: > On Fri, Dec 30, 2016 at 11:03 PM, PePa <peterke...@passchier.net > <mailto:peterke...@passchier.net>> wrote: > > r=23; echo $r; echo -e "r=bc\necho $r" |bash > > You need to escape the |$| in the second echo statement so that |$r| is > not evaluated to |23| before being echoed. > >
