> $(xxx) is a word expansion, not a command. Bash will only pay attention to > the exit status of command substitution in one case (x=$(foo)). This > command substitution doesn't contribute to any other command's exit status, > especially `echo', and `set -e' doesn't cause the shell to pay attention > to it.
Thanks Chet, it's clear now. > Exiting in a subshell will never cause the parent shell to exit, > regardless of depth. This is not true in general. set -e; (exit 1); echo "I don't exist" >> I've tested this with set -e, set -E, an ERR trap, > All of those are useless and should be avoided. Ok, I'm not particularly interested in using them, I was just reinforcing my point. Best regards -- Carlos
