On Tue, 27 Aug 2013, Chris Down wrote:
On 2013-08-26 21:36, David Lehmann wrote:
My issue is that the resulting behavior in Exercise 1 does not make sense.
The resulting value of i should have no bearing on the exit code. If the
addition succeeded, the expression should return 0 (success). If i was not
an integer (e.g. i=hello), then I expect (( i++ )) to return a non-zero
error code.
...IMHO, of course.
That would be pretty much rewriting the entire way that (( works, since the
whole point is that it returns a status based upon having a return value that
is >0.
Rather, that it is != 0
Compare:
$ (( 0 )); echo "$?"
1
$ (( 1 )); echo "$?"
0
$ (( -1 )); echo "$?"
0
--
Chris F.A. Johnson, <http://cfajohnson.com/>
Author:
Pro Bash Programming: Scripting the GNU/Linux Shell (2009, Apress)
Shell Scripting Recipes: A Problem-Solution Approach (2005, Apress)
