Re: Local variables overriding global constants

[Nikolai Kondrashov]

It works because both instances are local to a function and don't
exist outside their own functions.

Not true.

This:

bash -c 'a() { echo "$v"; }; b() { declare -r v=123; a; }; b'

Produces this:

123

Moreover, this:

    bash -c 'a() { v=2; }; b () { v=1; a; echo "$v"; }; b'

Produces this:

    2