> On 7/29/10 4:55 PM, Bernd Eggink wrote:
> > It seems that indirect expansion doesn't work with arrays:
> >
> > $ a=(x y z)
> > $ b=a
> > $ echo "${!b[0]} ${!b[1]} ${!b[2]}"
> > x
> >
> > Is that intended? The documentation isn't explicit about it.
> It does, but it doesn't work in the way you are trying. The `!' binds to
> an entire variable reference, in this case 'b[0]'. The idea behind that
> was to permit the use of an array of variable names, for instance, that
> could be easily referenced using indirect expansion.
> The following code will display
> "x variable y variable z variable"
> a=(x y z)
> x='x variable'
> y='y variable'
> z='z variable'
> echo "${!a[0]} ${!a[1]} ${!a[2]}"
> Chet
>--
>``The lyf so short, the craft so long to lerne.'' - Chaucer
> ``Ars longa, vita brevis'' - Hippocrates
> Chet Ramey, ITS, CWRU c...@case.edu
> http://cnswww.cns.cwru.edu/~chet/
I think that indirect reference for fash variable should be used literally.
$ a=(x y z)
$ b=a[@]
$ echo "${!b}" # this would work
Combine with Chet Ramey's reply, a strucure like below would work.
$ c=(a[0] a[1] a[2])
$ echo "${!c[0]} ${!c[1]} ${!c[2]}" #this would work too
--
View this message in context:
http://old.nabble.com/Indirect-expansion-and-arrays-tp29300541p34504291.html
Sent from the Gnu - Bash mailing list archive at Nabble.com.
