Hi All, Suddenly I found that ((i++)) is not supported on bash. Just try the following simple case: $i=0; ((i++)); echo $? And the result is 1 which means an error. I got the same result on GNU bash, version 4.1.2(1)-release (x86_64-redhat-linux-gnu) and GNU bash, version 4.1.10(4)-release (i686-pc-cygwin).
- BR, Ruochen
