> WHAT are you trying to DO? I think that you might completely miss my point. I try to explain it better. Let me know if this time it makes more sense to you.
I want to execute any command as if the 'execute.sh' does not present, except that I want to print the command so that I know want the command is executed. (This can be used when I call several commands in a script and I know what part of the output associated to what command). E.g. I can run ls > /tmp/tmp.txt When I call, execute.sh ls > /tmp/tmp.txt I want it actually to do echo "ls > /tmp/tmp.txt" ls > /tmp/tmp.txt Note that I could define execute.sh such that execute.sh "ls > /tmp/tmp.txt" means echo "ls > /tmp/tmp.txt" eval "ls > /tmp/tmp.txt" But this interface of execute.sh is not as good the previous one. Note that there could be other symbols that bash normal process, such as '2>&1'. I'm looking for a general solution, Pierre's answer is not as general as I want. The FAQ http://mywiki.wooledge.org/BashFAQ/050 doesn't really answer my question. BTW, where is the help-bash mailing list mentioned (at least not on bash home page)? I have never seen it before. http://tiswww.case.edu/php/chet/bash/bashtop.html -- Regards, Peng
