Ha. Indeed, if i use declare –A, it works.
But why is bash letting me use foo[bar]=something in the first place, if I
don’t declare foo as an associative array ?
Maybe the bug’s here.
D
--
Damien Nadé <dnade....@orange-ftgroup.com>
Astek Sud-Est pour France Télécom - FT/TGPF/OPF/PORTAIL/DOP/DEV/EAQS
Sophia Antipolis - France / Tel : 04 97 12 86 20
De : Pierre Gaston [mailto:pierre.gas...@gmail.com]
Envoyé : vendredi 31 décembre 2010 10:52
À : NADE Damien Ext DMGP/PORTAIL
Cc : bug-bash@gnu.org
Objet : Re: List of keys of an associative array
On Fri, Dec 31, 2010 at 11:38 AM,
<dnade....@orange-ftgroup.com<mailto:dnade....@orange-ftgroup.com>> wrote:
Hello
For regular arrays, we can get the list of keys by using the form
${!some_arr...@]}.
But this just doesn’t work for associative arrays.
${!some_associative_arr...@]} is actually 0. Is that a bug ?
Is there another way to get the list of keys available in an associative array ?
$ declare -A a;a[foo]=bar;a[baz]=bux;echo ${...@]}
baz foo
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