Marc Herbert <marc.herb...@gmail.com> writes: >> let intentionally returns status 1 if the value was 0; and status > 1 if >> there was an error. Why? So you can do loops such as: >> >> countdown=10 >> while let countdown--; do ... ; done >> >>> Why does this happen? Is it 'by design'? >> >> Yes. The same as for 'expr' which is standardized by POSIX to have the >> same behavior. > > This is a design mistake: it trades a few characters for a lot of confusion.
You can always choose to ignore the exit status. The converse is not true. Andreas. -- Andreas Schwab, sch...@linux-m68k.org GPG Key fingerprint = 58CA 54C7 6D53 942B 1756 01D3 44D5 214B 8276 4ED5 "And now for something completely different."
