On Wed, 27 Jan 2010, Sharuzzaman Ahmat Raslan wrote:
> I found the behaviour of the function below is a little bit odd. Appreciate
> if someone can share his/her knowledge regarding the behaviour.
>
> The output of the script will be:
>
> sharuzza...@debian:~$ ./case1.sh
> Nice behaviour,
>
> Somehow, the backtick for foo() execute the function, echoing the correct
> output, but fails to set the variable $gang to the correct value. Because of
> that, the function bar() did not echoing anything because the variable $gang
> is null.
>
> I would expect that $gang is set with the correct value and function bar()
> will work after that.
...
> #startscript----------
> #!/bin/bash
>
> # test case for variable assignment in string returning function
> # case 1: function with echo
>
> name="optimus"
>
> foo () {
> if [ "$name" = "optimus" ]
> then
> gang="good"
> echo "Nice behaviour"
> else
> gang="bad"
> echo "Naughty behaviour"
> fi
> }
>
> bar () {
> case "$gang" in
>
> good)
> echo "autobot"
> ;;
>
> bad)
> echo "decepticon"
> ;;
> esac
> }
>
> behaviour=`foo`
> group=`bar`
>
> echo $behaviour,$group
> #endscript------------------------
name="optimus"
foo () {
if [ "$name" = "optimus" ]
then
gang="good"
echo "Nice behaviour"
return 0
else
gang="bad"
echo "Naughty behaviour"
return 1
fi
}
bar () {
case "$gang" in
good)
echo "autobot"
return 0
;;
bad)
echo "decepticon"
return 1
;;
esac
}
behaviour=`foo` && gang=good || gang=bad
group=`bar` && gang=good || gang=bad
echo $behaviour,$group
--
Chris F.A. Johnson <http://cfajohnson.com>
===================================================================
Author:
Shell Scripting Recipes: A Problem-Solution Approach (2005, Apress)
Pro Bash Programming: Scripting the GNU/Linux Shell (2009, Apress)
