Sorry guys, I need to take it a step further and am hitting a wall at the
moment;
I need to take two results (from you examples), compare them and get a final
result. What I have thus far is;
operation()
{
echo >> $LOG
echo Running operation>> $LOG
for i in a b
do
mkdir $DIR/dir$i
cd $DIR/dir$i
date1=$SECONDS
operation
date2=$SECONDS
interval$i=$(($date2 - $date1)) #1st & 2nd errors
echo Operation took $interval second. >> $LOG
rm -rf *
cd /
umount $DIR
done
echo The 2nd time difference should be quicker than the 1st >> $LOG
interval=$(($interval8 - $interval2048)) >> $LOG #3rd error
if test 5 -gt "$interval"; then
echo fail
else
echo pass
fi
}
I'm getting the errors;
./file.sh: line x: intervala=1: command not found
./file.sh: line x: intervalb=1: command not found
./file.sh: line x: - : syntax error: operand expected (error token is " ")
It seems so simple in my head, but I don't know how to execute it...
Any help would be greatly appreciated.
Thanks
Matthew.
Matthew_S wrote:
>
> Thanks Paul and Chet;
>
> They both do the same thing and that's exactly what I was looking for.
>
> Thanks again,
>
> Matthew.
>
>
> Chet Ramey wrote:
>>
>> Paul Jarc wrote:
>>
>>> date1=`perl -e 'print time()'`
>>> ...
>>> date2=`perl -e 'print time()'`
>>> interval=`expr "$date2" - "$date1"`
>>
>> This general approach can be used without invoking any external programs:
>>
>> date1=$SECONDS
>> ...
>> date2=$SECONDS
>> interval=$(( $date2 - $date1 ))
>>
>> Chet
>> --
>> ``The lyf so short, the craft so long to lerne.'' - Chaucer
>> Live Strong. No day but today.
>> Chet Ramey, ITS, CWRU [EMAIL PROTECTED]
>> http://cnswww.cns.cwru.edu/~chet/
>>
>>
>> _______________________________________________
>> Bug-bash mailing list
>> Bug-bash@gnu.org
>> http://lists.gnu.org/mailman/listinfo/bug-bash
>>
>>
>
>
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