Configuration Information [Automatically generated, do not change]:
Machine: i686
OS: linux-gnu
Compiler: gcc
Compilation CFLAGS: -DPROGRAM='bash' -DCONF_HOSTTYPE='i686'
-DCONF_OSTYPE='linux-gnu' -DCONF_MACHTYPE='i686-pc-linux-gnu'
-DCONF_VENDOR='pc' -DLOCALEDIR='/tmp/share/locale' -DPACKAGE='bash' -DSHELL
-DHAVE_CONFIG_H -I. -I. -I./include -I./lib -g -O2
uname output: Linux boostbox 2.6.13-rc6 #1 Tue Aug 9 21:45:47 CEST 2005 i686
AMD Duron(tm) Processor AuthenticAMD GNU/Linux
Machine Type: i686-pc-linux-gnu
Bash Version: 3.0
Patch Level: 16
Release Status: release
Description:
If I localise IFS in a function, and then unset it, it gets unset. However, if I
then use an unquoted variable, it doesn't actually get split. This is what I expect from
IFS="", not from unset IFS.
Repeat-By:
var="a b c"
f() {
local IFS
unset IFS
echo ${IFS+set} # shows nothing, meaning IFS is really unset
echo ${var} # shows "a b c" rather than "a b c" (without
quotes)
}
f
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