Hello Jürgen,
I agree with your case 1/2 Statement.
The examples I was showing is actually "off by 1".
I was referring to
(1/3⊃V)←1
having
a←1
b←'ABC'
c←3 3⍴⍳9
V←a b c
(3⊃V)
1 2 3
4 5 6
7 8 9
As expected with case 1:
(3⊃V)←1
V
1 ABC 1
V←a b c
Not expected:
(*1/*3⊃V)←1
V
1 ABC 1
Expected:
(1/3⊃V)←1
V
1 ABC 1 1 1
1 1 1
1 1 1
as with
(1/c)←1
c
1 1 1
1 1 1
1 1 1
And that's Dyalog too.
Please restore compatibility:-)
Best Regards
Hans-Peter
Am 06.03.23 um 16:10 schrieb Dr. Jürgen Sauermann:
Gentlemen,
thanks for the discussion, fixed in *SVN 1655*.
Hans-Peter, I am sorry that this change creates an incompatibility in
your code.
My thinking for the old solution was this:
* V←0 0 0** ◊ V←1 ◊ V ∩ case 1.**
**1**
**
** V←0 0 0** ◊ V[]←1 ◊ V ⍝ case 2.**
**1 1 1**
*
This applies to GNU APL, APL2, and Dyalog. The question is then if
(A⊃V) in
(A⊃B)←X should behave like case 1 or like case 2 above. The case (A⊃B)←X
with nested (A⊃B)is described neither in the "IBM APL2 Language Reference"
nor in the "ISO 13751" standard, leaving some room for interpretation.
However, both APL2 and Dyalog agree on case 1 and therefore I changed
GNU APL to behave the same.
Best Regards,
Jürgen
On 3/4/23 8:25 PM, Hans-Peter Sorge wrote:
Hi,
Works as expected
⊃'Sue' 'Maria' 'Annalisa'
is an array 3 by 8.
⊂⊃'Susan' 'Mary' 'Annalisa'
is an element (⊂) of a 3 by 8 array (⊃'Susan' 'Mary' 'Annalisa' ).
Finally each element in ⊃'Sue' 'Maria' 'Annalisa' gets assigned an
array of ⊃'Susan' 'Mary' 'Annalisa'
Greetings
Hans-Peter
Am 04.03.23 um 16:53 schrieb Mr. Sunday:
Hi,
I have an issue with reassigning an element of a nested array. Here
is an example.
14535:15a:~% apl --version
BUILDTAG:
---------
Project: GNU APL
Version / SVN: 1.8 / SVN: 1651M
Build Date: 2023-03-02 00:25:07 UTC
Build OS: Darwin 21.6.0 x86_64
config.status: default ./configure options
Archive SVN: 1621
var←0 0 0 ⋄ (1⊃var)←5 4 ⋄ (2⊃var)←3 4⍴⍳12 ⋄ (3⊃var)←⊃'Sue'
'Maria' 'Annalisa' ⋄ var ⋄ (3⊃var)←⊂⊃'Susan' 'Mary' 'Annalisa' ⋄ var
┌→────────────────────────────┐
│┌→──┐ ┌→─────────┐ ┌→───────┐│
││5 4│ ↓1 2 3 4│ ↓Sue ││
│└───┘ │5 6 7 8│ │Maria ││
│ │9 10 11 12│ │Annalisa││
│ └──────────┘ └────────┘│
└ϵ────────────────────────────┘
┌→───────────────────────────────────────────────────────────────────────────────────────────────────────────┐
│┌→──┐ ┌→─────────┐
┌→──────────────────────────────────────────────────────────────────────────────────────┐│
││5 4│ ↓1 2 3 4│ ↓┌→───────┐ ┌→───────┐ ┌→───────┐ ┌→───────┐
┌→───────┐ ┌→───────┐ ┌→───────┐ ┌→───────┐││
│└───┘ │5 6 7 8│ │↓Susan │ ↓Susan │ ↓Susan │ ↓Susan │
↓Susan │ ↓Susan │ ↓Susan │ ↓Susan │││
│ │9 10 11 12│ ││Mary │ │Mary │ │Mary │ │Mary │
│Mary │ │Mary │ │Mary │ │Mary │││
│ └──────────┘ ││Annalisa│ │Annalisa│ │Annalisa│ │Annalisa│
│Annalisa│ │Annalisa│ │Annalisa│ │Annalisa│││
│ │└────────┘ └────────┘ └────────┘ └────────┘
└────────┘ └────────┘ └────────┘ └────────┘││
│ │ ││
│ │┌→───────┐ ┌→───────┐ ┌→───────┐ ┌→───────┐
┌→───────┐ ┌→───────┐ ┌→───────┐ ┌→───────┐││
│ │↓Susan │ ↓Susan │ ↓Susan │ ↓Susan │
↓Susan │ ↓Susan │ ↓Susan │ ↓Susan │││
│ ││Mary │ │Mary │ │Mary │ │Mary │
│Mary │ │Mary │ │Mary │ │Mary │││
│ ││Annalisa│ │Annalisa│ │Annalisa│ │Annalisa│
│Annalisa│ │Annalisa│ │Annalisa│ │Annalisa│││
│ │└────────┘ └────────┘ └────────┘ └────────┘
└────────┘ └────────┘ └────────┘ └────────┘││
│ │ ││
│ │┌→───────┐ ┌→───────┐ ┌→───────┐ ┌→───────┐
┌→───────┐ ┌→───────┐ ┌→───────┐ ┌→───────┐││
│ │↓Susan │ ↓Susan │ ↓Susan │ ↓Susan │
↓Susan │ ↓Susan │ ↓Susan │ ↓Susan │││
│ ││Mary │ │Mary │ │Mary │ │Mary │
│Mary │ │Mary │ │Mary │ │Mary │││
│ ││Annalisa│ │Annalisa│ │Annalisa│ │Annalisa│
│Annalisa│ │Annalisa│ │Annalisa│ │Annalisa│││
│ │└────────┘ └────────┘ └────────┘ └────────┘
└────────┘ └────────┘ └────────┘ └────────┘││
│
└ϵ──────────────────────────────────────────────────────────────────────────────────────┘│
└ϵϵ──────────────────────────────────────────────────────────────────────────────────────────────────────────┘
-- Everyday is Sunday.
