The following expression should work, if I'm reading the ISO spec correctly:
⊃ 3 (1 2) (2 2 ⍴ 0 1 2 3) It does work on Dyalog, and gives the expected result. Regards, Elias
The following expression should work, if I'm reading the ISO spec correctly:
⊃ 3 (1 2) (2 2 ⍴ 0 1 2 3) It does work on Dyalog, and gives the expected result. Regards, Elias