On 8 July 2016 at 09:24, Jay Foad wrote: > So if A and B are vectors, Z is a scalar whose single item is f/AgB. Hence Z > itself is ⊂f/AgB.
I think you are right that it should be ⊂f/AgB. I stand corrected. But I was looking at the evaluation sequence just below the informal description you quoted and after some reshaping and scalar expansion it says: > If A1 and B1 are both vectors, return f/A1 g B1. > Otherwise, set Z to an array such that (...) Now I think this is an error and this statement should be simply omitted because the subsequent description of how to form Z works for vectors too and would result in an enclosed value, but this is where I got it from. -k
