Excuse me if that wasn’t clear. 1+/⍳5 is the correct behavior. Replacing +
with {⍺+⍵} should give the exact result.
1+/⍳5
1 2 3 4 5
1{⍺+⍵}/⍳5
1 2 3 4 5
NARS is wrong in my opinion.
> On Jun 13, 2016, at 9:47 PM, Christian Robert <christian.rob...@polymtl.ca>
> wrote:
>
> How was that outputting *before* svn 740 ?
>
> On 2016-06-13 22:11, Xiao-Yong Jin wrote:
>> Hello,
>>
>> It breaks when the left argument is 1. In addition, with the internal
>> macros, the si stack is polluted.
>>
>> 1+/⍳5
>> 1 2 3 4 5
>
> NARS2000 give the exact same result:
>
> 1+/⍳5
> 1 2 3 4 5
>
> quite strange, not sure what this should output, so, in gnuapl:
>
> 1+/⍳5
> 1 2 3 4 5
> 2+/⍳5
> 3 5 7 9
> 10+/⍳5
> DOMAIN ERROR
> 10+/⍳5
> ^ ^
> 3+/⍳5
> 6 9 12
> 4+/⍳5
> 10 14
> 5+/⍳5
> 15
> 6+/⍳5
>
> 7+/⍳5
> DOMAIN ERROR
> 7+/⍳5
> ^ ^
>
> I really don't know what this syntax is supposed to do, but it has a
> fair/straight pattern.
>
>
>> 1{⍺+⍵}/⍳5
>> INDEX ERROR
>> μ-Z__pA_LO_REDUCE_X_B[5] μ-T←⊂(⊃μ-B1[μ-H;μ-a-μ-M;μ-L])μ-LO⊃μ-T
>> ^ ^
>
> NARS200 give here:
>
> 1{⍺+⍵}/⍳5
> DOMAIN ERROR
> 1{⍺+⍵}/⍳5
> ∧
>
> my 2 cents, (still newbie and will be for years)
>
> Xtian.
>> )sis
>> μ-Z__pA_LO_REDUCE_X_B[5] μ-T←⊂(⊃μ-B1[μ-H;μ-a-μ-M;μ-L])μ-LO⊃μ-T
>> ^ ^
>> ⋆ 1{⍺+⍵}/⍳5
>> ^
>>
>> )sinl
>> μ-Z__pA_LO_REDUCE_X_B[5] μ-Z μ-A μ-LO μ-B μ-B1 μ-rho_Z μ-rho_B1 μ-T μ-H μ-M
>> μ-L μ-a μ-N μ-I μ-I_max
>> ⋆
>>
>> Best,
>> Xiao-Yong
>>
>>
>>
