On Thu, May 19, 2016 at 12:37 AM, Xiao-Yong Jin wrote: > Now, > (22⍴8)⊤2⊥63⍴1 > 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 > > Dyalog does the same thing. > Can someone please explain to me why?
Because the result of ⊥ doesn't fit into integer and it gets converted to a floating point number which makes it lose precision. This is contrary to what you would like, sorry about that, but now (¯1+2*63)=2⊥63⍴1 which is mathematically correct; although it's also true that (2*63)=¯1+2*63. -k
