This used to work, but now gives a SYNTAX ERROR pkg⍙PAGER ⍕h1⍪h2⍪(⊂[2](5 3⍴'???LBLVARFUNOPR')[k+⎕io;]),[1.5]n
Replacing the above with these two lines works: zz←(5 3⍴'???LBLVARFUNOPR')[k+⎕io;] pkg⍙PAGER ⍕h1⍪h2⍪(⊂[2]zz),[1.5]n Which is the same thing except for replacing a subexpression with a variable. -- "The secret to creativity is knowing how to hide your sources." Albert Einstein http://soundcloud.com/davidlamkins http://reverbnation.com/lamkins http://reverbnation.com/lcw http://lamkins-guitar.com/ http://lamkins.net/ http://successful-lisp.com/
